**Figure 4. Dihedral Angle α**

Referring to Fig. 4, since b and c both have endpoints on circle C, Δabc is an isosceles triangle with dihedral angle between the two equal sides. If we construct a great circle arc from point S_{C} to midpoint D of side a, we will bisect Δabc into two congruent right spherical triangles.

The bisected dihedral angle at S_{C}, and side c = b = . We can solve for the remaining dihedral angle α at P, or at S_{N}, since these are equal. Since side c is perpendicular (Fig. 4) to the great circle arc made by plane B, this dihedral angle at P will be α.

Then, solving for side a (which was bisected) we get:

Also, because we are using a unit sphere,

(Unit sphere center S_{O} can move up or down along the z-axis and the north pole will remain the north pole and circle C will still pass though the pole S_{N} because angle changes accordingly in order to keep this true.